0=220x-2000-2x^2

Solution for 0=220x-2000-2x^2 equation:

0=220x-2000-2x^2

We move all terms to the left:

0-(220x-2000-2x^2)=0

We add all the numbers together, and all the variables

-(220x-2000-2x^2)=0

We get rid of parentheses

2x^2-220x+2000=0

a = 2; b = -220; c = +2000;
Δ = b2-4ac
Δ = -2202-4·2·2000
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-220)-180}{2*2}=\frac{40}{4}
=10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-220)+180}{2*2}=\frac{400}{4}
=100
$